21playerBJ
New Member
TXtourplayer,
I understand what you are saying, but if you base it on a relative percentage, not the actual or total chip count, then your 3rd place finisher(s) advancing are picked fairly........all are compared to a base number of 100% of the chip count of the person winning the table that they were on. The percentage calculation puts everyone on a level playing field. The percentage number accounts for the toughness or easyness of the table they were on.
Easy table = alot of chip counts should be high
Hard table = alot of chip counts should be low
Players at their table are compared to the winner of their table. The % calculation takes that into account to puts all players on a scale of 1 to 100. I would also like to suggest that it is highly unlilkely that there would be a tie, considering all of the combination of chip counts that there could be. And then for the percentage to be the same (a tie) on the highest percent being determined (in order to advance) would be an astronomical coincidence. There would be a much greater likelyhood of a tie in a chip count at a table, meaning that either both who tied advance, or that there would be a play-off or roll-off or use of some other tiebreaker in order to ensure that only the top two advanced. Of course, if three players advanced from a table due to a tie in the chip count and that came in an early round, it could very well be that one of the tables in the subsequent round(s) would have one too many players, making the tables 'unbalanced".
Let the wild card players advance due to their table play, not due to the luck of the draw.
I understand what you are saying, but if you base it on a relative percentage, not the actual or total chip count, then your 3rd place finisher(s) advancing are picked fairly........all are compared to a base number of 100% of the chip count of the person winning the table that they were on. The percentage calculation puts everyone on a level playing field. The percentage number accounts for the toughness or easyness of the table they were on.
Easy table = alot of chip counts should be high
Hard table = alot of chip counts should be low
Players at their table are compared to the winner of their table. The % calculation takes that into account to puts all players on a scale of 1 to 100. I would also like to suggest that it is highly unlilkely that there would be a tie, considering all of the combination of chip counts that there could be. And then for the percentage to be the same (a tie) on the highest percent being determined (in order to advance) would be an astronomical coincidence. There would be a much greater likelyhood of a tie in a chip count at a table, meaning that either both who tied advance, or that there would be a play-off or roll-off or use of some other tiebreaker in order to ensure that only the top two advanced. Of course, if three players advanced from a table due to a tie in the chip count and that came in an early round, it could very well be that one of the tables in the subsequent round(s) would have one too many players, making the tables 'unbalanced".
Let the wild card players advance due to their table play, not due to the luck of the draw.