PlayHunter
Active Member
VESRSION1: Hand 9 out of 10. Min/Max bet 100/500 and no surrender.
BR1 (me) 1256 chips and BR2 1228 chips.
BR2 first to act on this hand and bet 250, then BR1 bet 255.
BR2 received a hard 17 and stand, Dealer up card 7 and BR1 hard 13.
I did hit, received a 10 and busted. Dealer also busted. OUCH!
It felt so bad, that made me think at this following scenario:
VERSION2: Same details, but this time BR1 bets first on this next to last hand.
So, BR1 1256 chips bet 113 and BR2 1228 chips bets only 255. (or less)
In this case, I should stand or still hit on my hard 13 ? (but if it were a hard 12 instead ?) (I am thinking that if I stand on this hand and lose I can take the high on the last hand, but if I hit and bust and a full swing will happen, then BR2 will then have a 0.75+ maxbet and I would be in very big troubles on the last hand?)
BR1 (me) 1256 chips and BR2 1228 chips.
BR2 first to act on this hand and bet 250, then BR1 bet 255.
BR2 received a hard 17 and stand, Dealer up card 7 and BR1 hard 13.
I did hit, received a 10 and busted. Dealer also busted. OUCH!
It felt so bad, that made me think at this following scenario:
VERSION2: Same details, but this time BR1 bets first on this next to last hand.
So, BR1 1256 chips bet 113 and BR2 1228 chips bets only 255. (or less)
In this case, I should stand or still hit on my hard 13 ? (but if it were a hard 12 instead ?) (I am thinking that if I stand on this hand and lose I can take the high on the last hand, but if I hit and bust and a full swing will happen, then BR2 will then have a 0.75+ maxbet and I would be in very big troubles on the last hand?)
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