The strategy table for the strong variation to Curt's revenge might be mistaken in the row for hard hands to be doubled and BR1 has stood stiff. In the column under dealer's 2 it should read 11. Under 3 and 4 it should read 10-11. Everything else in the "stiff" row under hard hands to be doubled is okay.
I got this idea after evaluating what happened to me today in GPC sit and play. I was BR2 down by 5 with position and took the low by a chip. BR1 and I both had over two max bets in our bankrolls. BR3 played first and busted out of contention. The other two were gone already. BR1 stood stiff against dealer 2. I stood on 12 against dealer 2, figuring my own hand was irrelevant and the count was negative, so I wanted to help the dealer out a little bit by leaving low cards in the deck. As it happens the dealer busted anyway and I walked away with my 9$ for 2nd place.
I got to thinking as I smoked a cigar on my patio, "What if I had a basic strategy double down instead of 12?" The chart says to play regular basic strategy, which in this case is to double down. But, is it really wiser to double down and give BR1 the low while taking back the high, when the dealer's chances of making a hand are this good? If I don't double down my own hand is irrelevant. My chances depend on whether the dealer busts or makes any hand. The dealer busting is a failure for me. My probability of failure with a dealer 2 is 35.35% according to Ken Smith's table at http://www.blackjackinfo.com/bjtourn-dealercharts.php#6DS17.
What if I had 11 instead of 12? If I double down, a push or win is a success for me; a loss is a failure. My probability of failure in this case rounds off to 34% according to C:\Blackjack Info\BlackjackInfo_com Blackjack Double Down Charts.htm. So I should double down 11 against 2. The difference in the expectation increases incrementally with dealer 3, 4, 5, and 6.
What if I had a 10? Now my probability of failure doubling down against dealer 2 rounds off to 37%. I'm actually better off hitting instead of doubling down by about 2%. With 10 against dealer 3 my probability of failure doubling down versus hitting is 36% versus 37.42%, so I'm better off doubling 10 against 3 than just hitting. Again the difference in expectation increases incrementally with dealer 4, 5, and 6.
Similar evaluations in the case of my 9 reveal that I'm better off hitting than doubling against dealer 3 and 4, but should double against dealer 5 and 6.
Any comments on this logic?
I got this idea after evaluating what happened to me today in GPC sit and play. I was BR2 down by 5 with position and took the low by a chip. BR1 and I both had over two max bets in our bankrolls. BR3 played first and busted out of contention. The other two were gone already. BR1 stood stiff against dealer 2. I stood on 12 against dealer 2, figuring my own hand was irrelevant and the count was negative, so I wanted to help the dealer out a little bit by leaving low cards in the deck. As it happens the dealer busted anyway and I walked away with my 9$ for 2nd place.
I got to thinking as I smoked a cigar on my patio, "What if I had a basic strategy double down instead of 12?" The chart says to play regular basic strategy, which in this case is to double down. But, is it really wiser to double down and give BR1 the low while taking back the high, when the dealer's chances of making a hand are this good? If I don't double down my own hand is irrelevant. My chances depend on whether the dealer busts or makes any hand. The dealer busting is a failure for me. My probability of failure with a dealer 2 is 35.35% according to Ken Smith's table at http://www.blackjackinfo.com/bjtourn-dealercharts.php#6DS17.
What if I had 11 instead of 12? If I double down, a push or win is a success for me; a loss is a failure. My probability of failure in this case rounds off to 34% according to C:\Blackjack Info\BlackjackInfo_com Blackjack Double Down Charts.htm. So I should double down 11 against 2. The difference in the expectation increases incrementally with dealer 3, 4, 5, and 6.
What if I had a 10? Now my probability of failure doubling down against dealer 2 rounds off to 37%. I'm actually better off hitting instead of doubling down by about 2%. With 10 against dealer 3 my probability of failure doubling down versus hitting is 36% versus 37.42%, so I'm better off doubling 10 against 3 than just hitting. Again the difference in expectation increases incrementally with dealer 4, 5, and 6.
Similar evaluations in the case of my 9 reveal that I'm better off hitting than doubling against dealer 3 and 4, but should double against dealer 5 and 6.
Any comments on this logic?
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