Jonny21
Active Member
I will be going to a casino that offers a bonus if you stay there. The bonus is a coupon that allows you to use it as an Ace for your first card at the start of any hand. According to a table from The Wizard of Odds, the value of that coupon is .504 or $5.04 on a $10.00 bet.
I plan to make as big a bet as they allow, at an opportune time,
so I wanted to see what my chances are of losing the bet. It looks like I would be expected to lose about 28% of these bets, yes?
If you could play 100 hands of $10.00 using the coupons,in a neutral deck, you would make $504.00
Breakdown would be:
31 Blackjacks = (4/13 X 100) = 31 X 15 = +465.00
On a little less than 2 of those, the dealer
would also have BJ, so you wouldn't get paid
(Dealer gets BJ about 1/20 of hands) = -30.00
So the blackjacks account for $435.00 of the advantge
For the other 69 hands, you net +80.00, so you must
win eight more than you lose. You push 9% of the time, (69 X .09 = about 6) That leave 63, so that means winning 35 and losing about 28.
Of course, I will have to be ready to split and and double the big bet if necessary.
Does this look about right? Thanks. Jonny
I plan to make as big a bet as they allow, at an opportune time,
If you could play 100 hands of $10.00 using the coupons,in a neutral deck, you would make $504.00
Breakdown would be:
31 Blackjacks = (4/13 X 100) = 31 X 15 = +465.00
On a little less than 2 of those, the dealer
would also have BJ, so you wouldn't get paid
(Dealer gets BJ about 1/20 of hands) = -30.00
So the blackjacks account for $435.00 of the advantge
For the other 69 hands, you net +80.00, so you must
win eight more than you lose. You push 9% of the time, (69 X .09 = about 6) That leave 63, so that means winning 35 and losing about 28.
Of course, I will have to be ready to split and and double the big bet if necessary.
Does this look about right? Thanks. Jonny