I'm not sure how the powers that be came to determine that 8, 16 and 24 were the right lengths for elimination hands. However, it seems to have a major flaw: The same player can be on the button for multiple elimination hands. The problem is that there is 8 hands between EH1 (EH=Elimination Hand) and EH2 (evenly divisible by 4) and 9 hands between EH2 and EH3 (evenly divisible by 3). That means that if exactly 5 players remain after EH1 (a common scenario), then the button on EH1 is expected to also be the button on EH2. If he miraculously survives this round, he is the designated button on EH3. This hardly seems fair to the button, but is a huge advantage to the guy you continually gets to act last.
My suggestion is that there be 7 hands between EH1 and EH2. And 7 hands between 2 and 3. Since there are never 7 people alive between 2 and 3, the button will never repeat (barring an early elimination). Some example orders would be 8,15,22,28 or 9,16,23,30.
My suggestion is that there be 7 hands between EH1 and EH2. And 7 hands between 2 and 3. Since there are never 7 people alive between 2 and 3, the button will never repeat (barring an early elimination). Some example orders would be 8,15,22,28 or 9,16,23,30.